![]() ![]() ![]() Arc 10 of eight x plus A X squared over one plus Taking the square of that. We can just arrange it a little bit two X. We first do the derivative of the outer function which is our 10 And that one is one over one plus The argument, which is eight x squared mhm times the derivative of X which is eight. We're going to have to use the chamber to do this and to use the chain rule. We know that the relative is equal to the director of the first function of X squared, which is two X time is the second function without a change arc tan of a X plus the first function times the derivative of the second function. Click Go to start the integral/antiderivative calculation. So what we should do is do use the problem Using the protocol. Variable of integration, integration bounds and more can be changed in Options. The first thing we noticed when we're going to do the derivatives and that we always should do is analyze the function we observed that this is a product of this function times dysfunction. In this situation, they want us to take the relative of this function X squared times are tan of X.
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